Total weight, w = 10 lbs.
Height of the bucket, h = 2 feet.
Distance walked, d = 100 ft.
Now, work done in moving the bucket at a height of 2 feet.
W = mgh
W = 2× 32.17×100
W = 6434 lbs ft²/s²
Work done in moving bucket in horizontal direction is zero because it is perpendicular to the force.
Therefore, work done is 6434 lbs ft²/s² .
Hence, this is the required solution.
Cos(r)=10/26
cos(s)=24/26
sin(r)=24/26
sin(s)=10/26
tan(r)=24/10
tan(s)=10/24
I hope these are right :)
Answer:
26
Step-by-step explanation:
cosθ = adjacent / hypotenuse
cos(26) = 18 / x
x= 18 / cos(26)
x= 27.82418 ≈ 20 (to nearest tenth)
Answer:
First, plot the y-intercept. The y-intercept is 1, so plot the point (0,1).
Then go up 2 points and to the right 3 points and plot a point there. (3,3)
We go to the right because the slope is positive.
Draw a line through the two points.
Step-by-step explanation:
y = mx+b
m = slope
b = y-intercept
