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Leto [7]
3 years ago
12

one light flashes every 2 minutes and another flashes every 7 minutes. If both lights flash together at 1pm, what is the first t

ime after 3pm that both light flash together again?
Mathematics
1 answer:
vovangra [49]3 years ago
6 0
Light A flashes every 2 minutes while light B flashes every 7. The goal is to figure out when both lights flash at the same time and then figure out the other part later. You have to find the common multiples of 7 and 2. Meaning that you have to find out which number can they both be multiplied into. In this case, it is 14 because 7 can be multiplied by 2 to get 14 and 2 can be multiplied by 7. So if every 14 minutes they flash together at the same time, now you need to find out what time AFTER 3 will they both flash. You know that they both flashed at 1:00 so they will flash again at 1:14 and 1:28 and so on, but you need to find out when is the soonest they will flash after 3. 2 hours after the 1:00 flash will be 3:00 so that is 120 minutes. 120 minutes divided by 14 minutes comes to 8.5 but you dont need the decimal. Just simply multiply 14 by 8 and that comes to 112 minutes and if you add that to 1:00 you get 2:52. so they flashed at 2:52 so the next time they flash will be 14 minutes after 2:52. Sorry for the super long answer
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Answer:

Width: 12 ft

Maximum area: 144 ft²

Step-by-step explanation:

A = 24x – x²

A = –x² + 24x

A = –(x² – 24x)

A = –(x² – 24x + 144) + 144

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Therefore, the maximum area of 144 ft² occurs at x = 12 ft.

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4 years ago
11.<br>The domain of f(x) is [4, 5, 6]. If f(x) = 3x + 2, what is the range?​
grigory [225]

Answer:

The range of the function is:

Range R = {14, 17, 20}

Step-by-step explanation:

Given the function

f(x) = 3x + 2

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

  • Range refers to all the possible sets of output values on the y-axis.

We are given that the domain of the function is:

Domain D = {4, 5, 6}

Now,

substituting x = 4 in the function

f(4) = 3(4) + 2

f(4) = 12 + 2

f(4) = 14

substituting x = 5 in the function

f(5) = 3(5) + 2

f(5) = 15 + 2

f(5) = 17

substituting x = 6 in the function

f(6) = 3(6) + 2

f(6) = 18 + 2

f(6) = 20

Thus, we conclude that:

at x = 4, y = 14

at x = 5, y = 17

at x = 6, y = 20

Thus, the range of the function is:

Range R = {14, 17, 20}

3 0
3 years ago
In math :
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8 0
3 years ago
Read 2 more answers
Find the value of c, rounded to the nearest tenth <br> A. 11<br> B. 14.3<br> C. 37.6<br> D. 7.4
Helga [31]

Answer:

D. The correct value of  c  = 7.4

Step-by-step explanation:

According to Tangent-Secant theorem:

"When a tangent and a secant are drawn from one single external point to a circle, square of the length of tangent segment must be equal to the product of lengths of whole secant segment and the exterior portion of secant segment."

Here, the external length of tangent segment = 10

Also, the length of internal segment  is 14 and c.

So, by the SECANT THEOREM:

(10)^2  = 14 \times c\\\implies c = \frac{100}{14} = 7.14

or, c  = 7. 1428

Now, rounding off the value of c = 7. 14 to the nearest tenth, we get

c = 7. 4

Hence the correct value of  c  = 7.4

8 0
4 years ago
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Answer:

a.240.15

Step-by-step explanation:

a.240.15

b.12.0075

c.252.1575

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