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8_murik_8 [283]
3 years ago
6

Rationalize the denominator 11/√8x

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

\frac{11 \times  \sqrt{8} x}{8x ^{2}}

Step-by-step explanation:

\frac{11 \times  \sqrt{8}x }{ \sqrt{8}x \times  \sqrt{8}  x}

\frac{11 \times  \sqrt{8} x}{8x {}^{2} }

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Answer:

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Step-by-step explanation:

The given quadratic equation is x^2+4x-21=0. We need to find the solution of this equation.

If the equation is in the form of ax^2+bx+c=0, then its solutions are given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7

So, the solutions of the quadratic equation are 3 and -7.      

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