Answer:
The bigger pizza has a diameter of 14 inches, or a radius of 14 / 2 = 7 inches.
The smaller pizza has a diameter of 12 inches, or a radius of 12 / 2 = 6 inches.
Step-by-step explanation:
The area of a circle is πR2 where R is the radius.
The difference in the size of the pizzas is
Area of bigger pizza - Area of smaller pizza
= π(7 inches)2 - π(6 inches)2 = = 49π inches2 - 36π inches2 = 13π inches2
Step-by-step explanation:
i think this is what you are asking for
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
12 rainy days because 16 divided by 4 is 4. SO, 4 times 3 is 12
