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3 years ago

Write the expression as a monomial in its standard form. 9/16p^7 ⋅ (-4/3p^4)

Mathematics

2 answers:

jonny [76]3 years ago

7 0

Answer:

-¾p¹¹

Step-by-step explanation:

9/16p^7 ⋅ (-4/3p^4)

(9/16 × -4/3) × p^(7+4)

-3/4 × p¹¹

-¾p¹¹

Aleksandr-060686 [28]3 years ago

6 0

Answer:

-3/4 p^11

Step-by-step explanation:

9/16p^7 ⋅ (-4/3p^4)

Multiply the numbers together

9/16 * -4/3 = -3/4

Now multiply the variables

p^7 * p^4

We know that a^b* a^c = a^(b+c)

p^(7+4) = p^11

Putting these back together

-3/4 p^11

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Four more than 3 times a number t written asfour

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Four more than 3 times a number t

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4 years ago

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zvonat [6]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?

Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

If $\bigtriangleup = 0$ , the equation has only one solution.

In this problem, we have that:

$3x^{2} + kx + 3 = 0$

$a = 3, b = k, c = 3$

$\bigtriangleup = b^{2} - 4ac$

$\bigtriangleup = k^{2} - 4*3*3$

$\bigtriangleup = k^{2} - 36$

We will only have one solution if $\bigtriangleup = 0$ . So

$\bigtriangleup = 0$

$k^{2} - 36 = 0$

$k^{2} = 36$

$k = \pm \sqrt{36}$

$k = \pm 6$

For k = 6 or k = -6, the equation will have exactly one solution.

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3 years ago

ABCD Is a rhombus .AC=8cm and BD=3.5 cm .what is the aera of the rhombus

Triss [41]

$d_1;\ d_2-the\ diagonals\ of\ the\ rhombus\\\\The\ area\ of\ the\ rhombus:A=\dfrac{d_1\cdot d_2}{2}.\\\\d_1=|AC|=8\ cm;\ d_2=|BD|=3.2\ cm\\\\A=\dfrac{8\cdot3.5}{2}=4\cdot3.5=\boxed{14\ (cm^2)}$

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3 years ago