All categories

3 years ago

When the product of 4 and 4 is divided by the sum of 4 and 4, what is the quotient?

Mathematics

1 answer:

Rashid [163]3 years ago

5 0

Answer: 2

Step-by-step explanation:

The product of 4*4= 16

The product of 4+4= 8

The quotient of 16÷8=2

Hope this helps

You might be interested in

Simplify please quick: 3x4=12-6

den301095 [7]

Answer:

Step-by-step explanation:

3 * 4 = 12 - 6

12 = 6

This statement is false

3 0

2 years ago

Read 2 more answers

If the area of the cube is 2 1/2 what is the surfece area

mariarad [96]

Answer:

37.5

Step-by-step explanation:

6 0

3 years ago

An elephant can run one over four mile in 36 seconds. Which of the following correctly shows this rate as miles per hour?

Ainat [17]

Answer:

C. One-fourth mile over thirty-six seconds = 25 miles per hour.

We have been given that an elephant can run one over four of a mile in 36 seconds.

To find elephant's rate in miles per hour, we will convert our given time in hours as shown below:

Therefore, option C is the correct choice.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How do i solve the equation 5n+4=-26

ozzi

You do

-26
-4
---
-30

5n=-30 so...

-30/5=-6

Therefore
n=-6

3 0

3 years ago

Read 2 more answers

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size n = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size n = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

3 years ago