<h3>
Answer: 29</h3>
=================================
Work Shown:
Solve the second equation for f(b)
2f(b) = 28
f(b) = 28/2
f(b) = 14
----------
Plug in x = b and solve for b
f(x) = 3x-1
f(b) = 3b-1 ... replace every x with b
14 = 3b-1 ..... plug in f(b) = 14
3b-1 = 14
3b = 14+1
3b = 15
b = 15/3
b = 5
-----------
f(x) = 3x-1
f(2b) = 3(2b)-1 .... replace every x with 2b
f(2b) = 3(2*5)-1 .... plug in b = 5
f(2b) = 3*10-1
f(2b) = 30-1
f(2b) = 29
Yes, it is fairly reasonable... if you round it..
however, if you want exact calculations, then it might not be so reasonable, because it will go over the total amount
so if you round it, then yes it is fairly reasonable
Answer:
37) -1/3
38) 8/5
39) 0
40) -2/3
Step-by-step explanation: