All categories

3 years ago

Please help! I need an immediate correct answer please see attachment thanks so much

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

3 0

Label the vertices A (- 3, - 2), B (- 7, - 3 ), D (- 4, - 5 )

and the centre of dilatation C (- 7, - 6 ), then

CA = a - c = < - 3, - 2 > - < - 7, - 6 > = < 4, 4 >

CA' = 3 < 4, 4 > = < 12, 12 >

A' = (- 7 + 12, - 6 + 12 ) = ( 5, 6 )

CB = b - c = < - 7, - 3 > - < - 7, - 6 > = < 0, 3 >

CB' = 3 < 0, 3 > = < 0, 9 >

B' = (- 7 + 0, - 6 + 9 ) = (- 7, 3 )

CD = d - c = < - 4, - 5 > - < - 7, - 6 > = < 3, 1 >

CD' = 3 < 3, 1 > = < 9, 3 >

D' = (- 7 + 9, - 6 + 3 ) = ( 2, - 3 )

Summarising

(- 3, - 2 ) ⇒ (5 , 6 )

(- 7, - 3 ) ⇒ (- 7, 3 )

(- 4, - 5 ) ⇒ (2, - 3 )

You might be interested in

How many times could 6 go into 6

saveliy_v [14]

6 can only go into 6 once

7 0

4 years ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 58.

Yanka [14]

Answer: 0.025

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].

The probability density function :-

$f(x)=\dfrac{1}{58-48}=\dfrac{1}{10}$

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-

$\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025$

Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025

Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025

5 0

3 years ago

Use the sliders to change the values of a, b, and c in the sine function. Which equation has a maximum at (negative StartFractio

marissa [1.9K]

Answer:

The answer is C on edge

y = –3 sin(2x)

4 0

3 years ago

Which of the following points is a solution to the system of linear inequalities?

Nadusha1986 [10]

Answer:

Step-by-step explanation:

2(-4)-1≤-5

-9≤-5

true

-(-4)-1>0

3>0

true

all the other options are false when u solve it

5 0

3 years ago

Jimmy made a trip to the ferry office and back. The trip there took two hours and the trip back took three hours. He averaged 20

sukhopar [10]

Answer:

60 mph

Step-by-step explanation:

We don't know how far Jimmy drives in each direction. Let this distance be d. Then, d = rate * time, and d = r(2 hours) (where r represents his speed while driving to the ferry).

But it's also true that d = (r - 20 mph)(3 hours).

Equating d = r(2 hours) and d = (r - 20 mph)(3 hours), we get:

r(2) = (r - 20)(3), or 2r = 3r - 60.

Subtracting 2r from both sides yields 0 = r - 60, so that r = 60 mph.

Jimmy averaged 60 mph on the outbound trip.

6 0

4 years ago