Answer:
C
Step-by-step explanation:
First you rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation
Second you solve it by using the formula of a straight line drawn on Cartesian coordinate system in which “y” is the vet risk axis and “x” the horizontal axis.
A jar of jelly beans contains 50 red gumballs , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly
select a jelly bean, then select another without
putting the first jelly bean back. What is the
probability that you draw two red jelly beans? This is Dependent because you didnt put the other jelly bean in thus changing the total nmber of jelly beans.
A jar of jelly beans contains 50 red gumballs<span> , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly select a jelly bean, then select another while replacing the first jelly bean back. What is the probability that you draw two red jelly beans? This is Independent because you put the other jelly bean in thus keeping the total number of jelly beans.</span>
Answer:
33.89
Step-by-step explanation:
the side lengths are the distances between the corner points of the triangle.
P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.
PQ = 6 - (-6) = 6 + 6 = 12
QR and RP are trickier.
we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.
QR :
QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97
QR = sqrt(97) ≈ 9.848857802
RP :
RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145
RP = sqrt(145) ≈ 12.04159458
the perimeter/circumference of the triangle is the sum of all 3 sides
= 12 + sqrt(97) + sqrt(145) ≈ 33.89
The answer is 90, there is 10 millimeters in 1 centimeter! So, if there is 9 centimeters, there will then be 90 millimeters!
Ps: I had my question up but someone reported it since I added a picture that would help you! :(
Hope this does help though! You can always do the jumping trick with meters! That's how I learned :)
