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3 years ago

Thanks for answering these 1. -2(n-6)

1 answer:

4 0

1) -2(n-6)

-2n+12

2) (5b-4)1/5
(5b-4)(1/5)
(5b)(1/5)+(-4)(1/5)

b+-4/5

3) 2/3(6y+9)
(2/3)(6y)+(2/3)(9)

4y+6

4) 4t-7t

-3t

5) -18v^2+23v^2

5v^2

6) 13q-30q

-17q

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The correct answer is B. 30 > 10

Explanation:

In mathematics and related fields, number lines are straight lines that display numbers using intervals this is useful to represent quantities visually, for example in graphs. Additionally, in number lines, numbers are organized in ascending order from left to right, for example, number 1 will be placed to the left of number 2. According to this, number 30 placed to the right of 10 will represent a higher quantity, considering the more you go to the right the higher the number is. Thus, 30 is greater than 10 (30 > 10).

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4 years ago

The smallest positive solution of tan bx = 2 is x = 0.3. Determine the general solution of tan bx = 2.

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The general solution of tan(b·x) = 2, given that the smallest positive solution is x = 0.3, is presented as follows;

$\mathbf{ x =0.3 + \dfrac{n \cdot \pi}{b}}$

The given smallest positive solution of tan (b·x) = 2 is x = 0.3

The general solution of tan (b·x + c) = m, is given as follows;

$\mathbf{x = \dfrac{\alpha - c}{b} + n \cdot \dfrac{\pi}{b}}$

α = arctan(m) = x₀

The minimum positive value of the general solution is therefore presented as follows;

$x_{min \ positive} = \dfrac{\alpha - c}{b} + 0 \times \dfrac{\pi}{b} = \dfrac{\alpha - c}{b}$

$\mathbf{x_{min \ positive} = \dfrac{\alpha - c}{b}}$

In the given function, tan (b·x), we therefore, have;

c = 0, m = 2, $\dfrac{\alpha - c}{b} = 0.3$

The general solution of tan(b·x) = 2, is therefore;

$\mathbf{x =0.3 + \dfrac{n \cdot \pi}{b}}$

Learn more about the general solution of a sine function here:

https://brainly.in/question/1549935

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