The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).
Answer: 1
Step-by-step explanation: Okay 1 + 1 =2 2 + 1 = 3 3 + 1 = 4 4 + 1 = 5 5 + 1 = 6 6 + 1 = 7 7 + 1 = 8 8 + 1 = 9 9 + 1 = 10 that is all of the first 2 rows now go down 10 + 1 = 11 11 + 1 = 12 12 x 0 = 0 and 0 + 1 = 1 hope it helps.
Answer:
13
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
Answer:
4.7976
Step-by-step explanation:
pachocko
