The data set represents the prices, in dollars, of the items students are selling for a fundraiser. 1, 1, 2, 3, 3, 4, 4, 4, 5, 5
lidiya [134]
To produce a box plot, we need the lowest and highest value from the data set. We also need the lower quartile (
), median (
), and upper quartile (
).
All these data and the box plot is shown in the diagram below
1. The probability that we select a red marble is 1/3.
We found this out by taking the amount of red marbles there are and the total amount of marbles. The total amount of marbles is 18 and there are red marbles. So, it would become 6 out of 18 or 6/18. Then, we simplify 6/18 to the simplest form. The greatest common factor of both of those numbers is 6. Lastly, we divide each of them by 6 to get the simplest form.
6/18 = (6/6)/(18/6)
(6/6)/(18/6) = 1/3
So, therefore, the theoretical probability of picking a red marble is 1/3.
2. The probability that we select a blue marble is 2/3.
We can find this out by taking the amount of blue marbles there are and the total amount of marbles. We know that the total amount of marble is 18 and there are 12 blue marbles. So, we simply get the GCF (greatest common factor) and divide them by it.
Greatest Common Factor of 12 and 18 = 6
12/18 = (12/6)/(18/6)
(12/6)/(18/6) = 2/3
Thus, the theoretical probability of picking a blue marble is 2/3.
Answer:
<h3>The x intercept is 1/2</h3><h3>The y intercept is - 4</h3>
Step-by-step explanation:
y = 8x - 4
First to find the y intercept let x = 0
Substitute the value of x into the equation
That's
y = 8(0) - 4
y = - 4
<h3>The y intercept is - 4</h3>
To find the x intercept let y = 0
Substitute the value of y into the equation
that's
8x - 4 = 0
8x = 4
Divide both sides by 8
x = 1/2
<h3>The x intercept is 1/2</h3>
Hope this helps you
Answer: (751.05, 766.95)
Step-by-step explanation:
We know that the confidence interval for population mean is given by :-
,
where 
=population standard deviation.
= sample mean
n= sample size
z* = Two-tailed critical z-value.
Given : 
n= 42
We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576
Now, the 99% confidence interval around the true population mean viscosity :-
![759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)](https://tex.z-dn.net/?f=759%5Cpm%20%282.5760%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B42%7D%7D%5C%5C%5C%5C%3D759%5Cpm%20%282.5760%29%283.086067%29%5C%5C%5C%5C%3D759%5Cpm7.9497%3D%28759-7.9497%2C%5C%20759%2B7.9497%29%5C%5D%5C%5C%3D%28751.0503%2C%5C%20766.9497%29%5Capprox%28751.05%2C%5C%20766.95%29)
∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)
