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hodyreva [135]
3 years ago
15

PLEASE HELP WITH SIGNIFICANT FIGURES *AWARDING BRAINEST ANSWER* ASAP

Mathematics
1 answer:
marishachu [46]3 years ago
4 0
1) 0.07 zeros only matter if there is a non-zero digit, as well as the decimal to the left of it
2)90,000 it would have been 89000 if the 972 had been an 872
3).00420 must include the last zero, it is considered significant because of the reason in number one
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First make it a fraction, then divide numerator by denominator
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3- Product of two expressions H.C.F=<br>A. H.CF<br>B. L.C.M<br>C. H.C.F + L.C.M<br>D. H.C.P x L.C.M​
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(i) The product of the two expressions is equal to the product of their factors. (ii) The product of the two expressions is equal to the product of their H.C.F. and L.C.M. 2.

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3 years ago
URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

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3 years ago
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kap26 [50]

Answer:

108pi

Step-by-step explanation:

We do not need to know the height and radius, as the formula for the volume of a cone is just a third of the volume of a cylinder. So we have 36pi * 3 or 108pi.

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