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Afina-wow [57]
3 years ago
13

Simplify the equation (-2.7)0

Mathematics
1 answer:
NikAS [45]3 years ago
5 0
(-2.7)0 = 0          [multiplication of 0 is 0]
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A shop owner offerad a 20% discount off the regular price of a mirror. The amount of the discount is 3$ what is the regular pric
Troyanec [42]

Answer:

$15

Step-by-step explanation:

$3 correspond is the 20% discount of the total price.

If the total price is x then you can express the discount as:

0.20x = 3

x = 3/0.20

x = 15

3 0
4 years ago
Which alternative will increase the probability of detecting a shift in the process average?
melamori03 [73]

Answer:

d. Taking larger samples more frequently

Step-by-step explanation:

The alternative that will increase the probability of detecting a shift in the process average is option D.

d. Taking larger samples more frequently .

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3 years ago
y varies directly as x and inversely as the square of z. y equals y=30 when x equals x=108 and z equals z=6. Find y when x equal
Slav-nsk [51]

Answer:

Step-by-step explanation:

That really easy Peary it’s not eieoruirbcbdkehbdbs shrine chdiej

4 0
3 years ago
Which of the following is the result of the equation below after completing
ICE Princess25 [194]

Answer:

C

Step-by-step explanation:

{x}^{2}  + 5x + 8 = 4 \\  =  >  {x}^{2}  + 2 \times  \frac{5}{2}  \times x +  \frac{25}{4}  +  \frac{7}{4}  = 4 \\  =  >  ({x +  \frac{5}{2} }^{2} ) +  \frac{7}{4}  = 4 \\  =  > ({x +  \frac{5}{2} }^{2} ) =  \frac{9}{4}

6 0
3 years ago
A business executive bought 40 stamps for
alekssr [168]

Answer:

32 33-cent stamps, 8 23-cent stamps

Step-by-step explanation:

In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.

To make our first equation, let's think about the number of stamps total we have. We can say:

x + y =40

<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>

Now, let's make an equation for the cost of these stamps.

0.33x + 0.23y = 12.40

<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>

So now, we have our two equations:

x + y =40\\0.33x+0.23y=12.40

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

x+y=40\\x=40-y

Now, let's put this into our second equation.

0.33x+0.23y=12.40\\0.33(40-y)+0.23y=12.40

Distribute, and solve for y.

13.2-0.33y +0.23y =12.40\\13.2-0.1y=12.40\\-0.1y=-0.8\\y=8

Now, we plug this into one of our equations.

x+y=40\\x+8=40\\x=32

In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.

3 0
1 year ago
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