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Zina [86]
3 years ago
11

M N O P find the value of x and y I’m degrees

Mathematics
1 answer:
jeka943 years ago
3 0

Answer:

i dont kno anything

Step-by-step explanation:

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(5x-3)^2 -60x=(5x-3)^2
V125BC [204]

Answer:

x = 0

Step-by-step explanation:

3 0
3 years ago
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Prove that
Dovator [93]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

secx = \frac{1}{cosx} , cosecx = \frac{1}{sinx}

cotx = \frac{cosx}{sinx} , tanx = \frac{sinx}{cosx}

Consider the left side

secA cosecA - cotA

= \frac{1}{cosA} × \frac{1}{sinA} - \frac{cosA}{sinA}

= \frac{1}{cosAsinA} - \frac{cosA}{sinA}

= \frac{1-cos^2A}{cosAsinA}

= \frac{sin^2A}{cosAsinA} ( cancel sinA on numerator/ denominator )

= \frac{sinA}{cosA}

= tanA = right side ⇒ proven

5 0
3 years ago
The table shows whether members in a fishing group caught fish or did not catch fish and whether they fished from a boat or from
MariettaO [177]
The given scenario falls under the category of conditional probability. There are a total of 56 people in the fishing group described above. The probability that the a person caught a fish and fished from a boat is 24/56. The probability that he fished from a boat is (24+11)/56. For the conditional probability in this item is,
                                 P = (24/56) / ((24+11)/56) = 24/35 = 0.69
3 0
3 years ago
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What is the x-intercept of the line with this equation? <br><br>−5x + <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" i
Sonja [21]
The x-intercept is the point on the graph where it crosses the x-axis. It’s also the value of the x-coordinate when y = 0.

To find the x-intercept, set y = 0:

-5x + 1/5(0) = 15

-5x + 0 = 15
-5x = 15

Divide both sides by -5:

x = -3.

Therefore, the x-intercept is (-3, 0).

Please mark my answers as the Brainliest if your find my explanations helpful :)
7 0
2 years ago
The graph shows a reflection.<br><br> True or false: The pre-image and the image are not congruent.
LuckyWell [14K]

Answer:

False

Step-by-step explanation:

That is false

If the pre-image is reflected over any axis, the image will still be congruent to it

8 0
3 years ago
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