I guessed “doesn’t matter” but I really want to know why it might be that
1 answer:
I'm sorry, but the spinner that you choose does matter in this case.
For spinner A, there are 5 equal sections with a 1 being in only one of them as well. This gives you a
chance of landing on the number 1.
For spinner B, there are 6 equal sections with a 1 being in only one of them. This gives you a
chance of landing on the number 1 - a worse chance than if you were to use spinner A.
So for this question, you have a better chance of landing on number 1 if you choose to use spinner A.
For spinner A, there are 5 equal sections with a 1 being in only one of them as well. This gives you a
For spinner B, there are 6 equal sections with a 1 being in only one of them. This gives you a
So for this question, you have a better chance of landing on number 1 if you choose to use spinner A.
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A. We are going to form 7 digit numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
where the first digit cannot be 0 or 1.
so we have 8 choices for the 1. digit, and 10 choices for all the other 6 digits.
this means there are
possible numbers.
b.
consider the numbers which start with 911. There are
such numbers, since for the 4th, 5th, 6th and 7th digits we have 10 choices.
then we remove this number, from the one we found in a:
There are in total
numbers which don't start with 911.
Answer:
a.
b.7,990,000
where the first digit cannot be 0 or 1.
so we have 8 choices for the 1. digit, and 10 choices for all the other 6 digits.
this means there are
b.
consider the numbers which start with 911. There are
then we remove this number, from the one we found in a:
There are in total
Answer:
a.
b.7,990,000