The expression simplifies to 6x^(28/5)
hope this helps :)
(-1-3i)(-6-i)
=6+i+18i+3i^2
=3i^2+19i+6. Hope it help!
The t-value measures the size of the difference relative to the variation in your sample data. Put another way, T is simply the calculated difference represented in units of standard error. The greater the magnitude of T, the greater the evidence against the null hypothesis.
Answer:
The factored form would be (8g + 7h)(2g - 5h)
Step-by-step explanation:
In order to find this, we need to use factors of 16g^2 in the front of the parenthesis. We also need to use factors of -35h^2 in the second side. Now we try these in the parenthesis and FOIL until we get an appropriate middle term.
