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Alex_Xolod [135]
3 years ago
13

In geometry a is a location. It has no size. It is represented by a dot.

Mathematics
1 answer:
noname [10]3 years ago
7 0
It is a point. Hope this helps
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Please help, I'm super lost on this question even though I'm sure it's easy​
Tpy6a [65]

Answer:  C

Step-by-step explanation:

8 * 8 = 64

x = 8

7 0
4 years ago
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Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
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victus00 [196]
To find the constant proportionality you would need to find the cost of one ticket which would be 9 dollars
5 0
3 years ago
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Doss [256]

Answer:if you double all of the dimensions of a rectangular prism, you create a similar prism with a scale factor of 2. The surface area of the similar prism will increase as the square of the scale factor (22 = 4) and the volume will increase as the cube of the scale factor (23 = 8).

Step-by-step explanation:

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3 years ago
18,234.9+516.1 show your work
butalik [34]

Answer:

18,751

Step-by-step explanation:

18 234 . 9

516 . 1

----------------

18 751 . 0

----------------

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