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Leno4ka [110]
3 years ago
12

Will give brainlst Have a nice day

Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

Remember that the Pythagorean's theorem says that:

For a triangle rectangle with hypotenuse H and catheti A and B:

H^2 = A^2 + B^2

Here we also need to remember that the area of a square of side length L is:

area = L^2

Now let's solve this.

First, we start with two squares, one of side length a and the other of side length b.

Such that the complete area in the first image is:

area = a^2 + b^2

Now we draw two triangle rectangles with catheti a and b, and with hypotenuse c.

in step 3, we rotate those triangles in order to make a larger square, with side length c, with an area equal to:

area = c^2

Notice that we never added more shapes, so the area of the image did not change in all this process, then the initial area must be equal to the final area:

a^2 + b^2 = area = c^2

a^2 + b^2 = c^2

And remember that a and b are the catheti of the triangles, and c is the hypotenuse, then this is the Pythagorean's theorem.

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Talja [164]
Janet spent $45 in all
5 0
3 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
3 years ago
college algebra - please help The half-life for thorium-227 is 18.72 days. The amount A (in grams) of thorium-227 after t days f
Andreyy89

Answer:

t= 24.75 days

Step-by-step explanation:

Here A(t) is the amount of the element that remains after some time. So they tell us that find the time it takes to basically have 4 grams remaining so A(t) = 4

4 = 10 * 0.5 ^ (t/18.72)

0.4= 0.5 ^ (t/18.72)

t= 24.75 days

Answer should make sense because half life is around 18 days which means to go from 10 g to 5g would be somewhere around 18 days but we are going to 4 g so it takes more days

6 0
3 years ago
Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenu
Ede4ka [16]

Answer: The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

1:\sqrt{3}:2

Since Hypotenuse = 12 cm

So, it becomes,

2x=12\\\\x=\dfrac{12}{2}=6

So, Base would be

x=6\ cm

and Perpendicular would be

\sqrt{3}x=6\sqrt{3}

So, Area common to the both triangles would be

\dfrac{1}{2}\times base\times height\\\\=\dfrac{1}{2}\times 6\times 6\sqrt{3}\\\\=18\sqrt{3}\\\\=31.177

Hence, the area common to both triangle is 31.77 sq. cm.

4 0
3 years ago
PLZ HELP ASAP ON 3 A B AND C
viktelen [127]
A: From the graph, car B was traveling faster.

Because the line of car B is more steep than the line of car A.

B:
The lines cross at (2,80), this means that the two cars were traveling at the same distance (80 miles) at the same time (2 hours).

C:
Since the line passes through the points (0,0) and (2,80)

So the unit rate or slope is 40 mph.

The distance which car A traveled in the first four hours = 4x40= 160 mph
8 0
3 years ago
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