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Natasha2012 [34]
3 years ago
13

Solve the equation using factoring polynomials. (z+5)2z

Mathematics
1 answer:
Mkey [24]3 years ago
6 0
(x + 5)²z
(x + 5)(x+ 5)z
(x² + 5x + 5x + 25)z
(x² + 10x + 25)z
(x²)z + (10x)z + (25)z
x²z + 10xz + 25z
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The sum of 444 consecutive integers is 326326326.<br> What is the second number in this sequence?
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Answer:

82

Step-by-step explanation:

Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.

The sum of 4 consecutive numbers:

1st = x

2nd = x + 1

3rd = x + 2

4th = x + 3

The sum of 4 consecutive number is 326.

1st + 2nd + 3rd + 4th = 326

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Combine like terms:

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Then we subtract 6 from both sides to isolate 4x:

4x + 6 - 6 = 326 - 6

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Then we divide both sides by 4 to isolate x:

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x = 80

So the first number is 79

Now to get the second, let's just add 1.

80 + 1 = 81

Let's check if our answer would be correct:

80 + 81 + 82 + 83

= 326

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