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mote1985 [20]
3 years ago
11

2x+4(2x+7)=3(2x+4) What is x

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

x = -4

Step-by-step explanation:

2x+4(2x+7)=3(2x+4)

Distribute

2x+8x + 28 = 6x +12

Combine like terms

10x +28 = 6x +12

Subtract 6x from each side

10-6x+28 = 6x +12 -6x

4x +28 = 12

Subtract 28 from each side

4x+28-28 = 12-28

4x = -16

Divide each side by 4

4x/4 = -16/4

x = -4

pav-90 [236]3 years ago
6 0

Answer:

x = -4

Step-by-step explanation:

2x+4(2x+7)=3(2x+4)

2x + 8x + 28 = 6x + 12

10x + 28 = 6x + 12

4x = -16

x = -4

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AlexFokin [52]

5/3=1 2/3

17/6=2 5/6

16/5=3 1/5

9/4=2 1/4

7/2=3 1/2

Hope this helps!

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3 years ago
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3 years ago
A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c
slava [35]

Answer:

I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

\frac{dI}{dt}=a*I*(1000-I)

Rearranging and integrating

\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t

At the initial breakout (t=0) there was one trooper infected (I=1)

-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755

In two days (t=2) there were 5 troopers infected

-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725

Rearranging, we can model the number of infected troops (I) as

-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755}  \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

6 0
3 years ago
Find the area of a parallelogram with sides 6 and 12 and an angle of 60
KiRa [710]
Hello,

Let's assume h the heigth of the parallelogram

h/6=sin 60°==>h=√3/2*6=3√3
Area=3√3 * 12=36√3

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The population decrease caused by the plague led to an economic depression. Merchants and tradespeople had fewer people to whom
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Answer:

Due to the high number of deaths and the subsequent population reduction, the merchants - and tradespeople in general - saw a decrease in the sales of their merchandise. Once the number of infected people by the plague reduced was reduced at the end of the Fifteenth Century, the population grew exponentially, thus creating a higher demand for services and goods.

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