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lidiya [134]
2 years ago
5

the us consumes an average of 5.5 million metrics of bananas per year. there are 316 million people in the us and there are 1000

kg in 1 metric ton. how many kilogram of bananas are consumed per person in a year?​
Mathematics
1 answer:
BARSIC [14]2 years ago
6 0

Answer:

17.4 Kg of banana per person per year.

Step-by-step explanation:

Given: US consume an average of 5.5 million metric of banana per year.

           US have 316 million people.

   

First lets convert the unit of banana consumption per year.

Remember; 1 metric ton= 1000 kg, 1 million= 1000000.

US consume an average of 5.5 million metric banana= 5500000\ metric\ ton\times 1000 \ kg= 5500000000\ kg

We know, there 316 million people= 316\ million \times 1000000= 316000000\ people

Now, finding number of kilogram of banana are consumed per person in a year.

Kg of banana consumed per person= \frac{Total\ banana\ consumed}{Total\ number\ people}

⇒ Kg of banana consumed per person= \frac{5500000000}{316000000}

⇒ Kg of banana consumed per person= \frac{5500}{316} = 17.4\ kg

∴ 17.4 kg of banana are consumed per person per year.

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Based on information from Harper’s Index, 37% of adult Americans believe in Extraterrestrials. Out of a random sample of 100 adu
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Answer:

z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

Step-by-step explanation:

We have a prortion test.

P₀  =  37 %         P₀  = 0,37

sample size  =  n  =  100

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One tail-test  (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.

1.-Hypothesis:

H₀      null hypothesis                        P₀  =  0,37

Hₐ  alternative hypothesis                P₀  >  0,37

2.-Confidence interval 95 %

α  =   0,05        and    z(c)  =  1.64

3.-Compute of z(s)

z(s)  =  [  P  -  P₀  ]  /√(P₀Q₀/n) ]  

z(s)  =  [ (  0,47  -  0,37  ) /  √0.37*0,63/100

z(s)  = 0,1 /√0,2331/100     ⇒   z(s)  = 0,1 /0,048

z(s)  = 2.08

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z(s) > z(c)        2.08  > 1.64

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z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

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Answer:

The area of a label is 62.8\ in^{2}

Step-by-step explanation:

we know that

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we have that

A can is 4 inches wide

so

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Answer:

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=======================

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