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3 years ago

URGENT!! LAW OF SINES WORK

Mathematics

1 answer:

Lynna [10]3 years ago

6 0

Answer:

1. 7.1 cm

2. 10.9 cm

Step-by-step explanation:

1. You know the legs of a right triangle must be shorter than the hypotenuse. The only answer choice shorter than 8 cm is 7.1 cm.

2. By the Law of Sines, ...

AB/AC = sin(ACB)/sin(B)

AB = AC·sin(72°)/sin(38°) = 1.545·AC

The approximate value of AC from problem 1 is sufficient to get you close to the answer.

AB ≈ 7.1×1.545 ≈ 10.9 . . . cm

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

What is a pie chart in mathematics

Ymorist [56]

Answer:

A pie chart is a type of graph that represents the data in a circular graph.

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2 years ago

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Which coordinate divides the directed line segment from -10 At J to23 at K in the ratio of 2 to 1

CaHeK987 [17]

Answer:

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3 years ago

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3 years ago

51% of the tickets sold at a school carnival were early-admission tickets. If the school sold 100 tickets in all, how many early

saul85 [17]

Answer:

51 were the total number of the tickets sold at a school carnival were early-admission tickets.

Step-by-step explanation:

Total number of tickets sold by = 100

Let $x$ be the early-admission tickets sold by the school.

As 51% of the tickets sold at a school carnival were early-admission tickets.

$x=\frac{51}{100}\times 100$

$= 51$

Therefore, 51 were the total number of the tickets sold at a school carnival were early-admission tickets.

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3 years ago