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mariarad [96]
3 years ago
6

Isaac applied the steps below to find the product of (4.2)(–5.4). Step 1: (4.2)(–5.4) = (–5.4)(4.2) Step 2: = (–5.4)(4) + (–5.4)

(0.2) Step 3: = (–21.6) + (–1.08) Step 4: = –22.68 Which step shows where Isaac applied the distributive property?
Mathematics
2 answers:
pentagon [3]3 years ago
8 0

Answer:

step 2

Step-by-step explanation:

I took the test

skelet666 [1.2K]3 years ago
7 0

Answer:

Step 2

Step-by-step explanation:

Distributive Property: a(b+c)=ab+ac

Isaac's Steps are outlined below:

\text{Step 1:} (4.2)(-5.4) = (-5.4)(4.2) \\\\\text{Step 2:} = (-5.4)(4) + (-5.4)(0.2) \\\\\text{Step 3:} = (-21.6) + (-1.08) \\\\\text{Step 4:} = -22.68

We observe that in Step 2:

(-5.4)(4.2)=(-5.4)(4+0.2)=(-5.4)(4) + (-5.4)(0.2)

Therefore, Isaac applied the distributive property in Step 2.

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Rewrite the given transform as

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Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

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2 years ago
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Nadusha1986 [10]

Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given;

dimension of the smaller triangle =  4.5cm 6cm and 8 cm.

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7 0
3 years ago
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