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Rudik [331]
3 years ago
5

Help with geometry, Find the value of x. Round the length to the nearest tenth.

Mathematics
1 answer:
larisa86 [58]3 years ago
5 0

Answer:

  • it is 9.8 yards wide or 1.8 which is 9.8
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Please help me with my homework<br><br> <img src="https://tex.z-dn.net/?f=%5Cbf%7B%28x%2B9%29%5E5%7D" id="TexFormula1" title="\b
Brut [27]

Answer:

x⁵+ 45x⁴+ 810x³+ 7290x²+ 32805x +59049

Step-by-step explanation:

Greetings !

Given expression

(x + 9) {}^{5}

write 5 as a sum

(x + 9) {}^{3 + 2}

use \: a {}^{m + n}  = a {}^{m}  \times a {}^{n} to \: expand \: the \: expression.

(x + 9) {}^{3}  \times (x + 9) {}^{2}

Use (a+b)³=a³+3a²b+b³ to expand the expression

(x {}^{3}  + 27x {}^{2}  + 243x + 729) \times (x + 9) {}^{2}

Use (a+b)²=a²+2ab+b² to the second expression to expand it

(x {}^{3}  + 27x {}^{2}  + 243x + 729) \times(x {}^{2}  + 18x + 81)

Finally, simplify the expression gives

x {}^{5}  + 45x {}^{4}  + 810x {}^{3}  + 7290x {}^{2}  + 32805x + 59049

Hope it helps!

3 0
2 years ago
Read 2 more answers
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea level, as a function of time is
balu736 [363]
If h is m above the ocean and your trying to find when the rocket reaches that ocean… as the function gives the height above the ocean at a given time, when the height equals 0 the rocket will have reached the ocean so solve for t when h=0. working out in the photo. i got t=48.88seconds

4 0
3 years ago
What is the correct simplified version of the expression 32x + 8 - 34x?
MakcuM [25]

Answer:

  -2x +8

Step-by-step explanation:

The terms involving x are "like" terms, so their coefficients are added when the terms are combined.

  = 32x -34x +8

  = (32 -34)x +8 . . . . . x is factored out according to the distributive property

  = -2x +8

5 0
3 years ago
A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

-16x^2+64x-5=0

For simplicity, divide both sides by -1:

16x^2-64x+5=0

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

Evaluate:

\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0
2 years ago
Figure AAA is a scale image of figure BBB.
Elan Coil [88]

Answer:

4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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