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jarptica [38.1K]
2 years ago
6

Which one is it please tell me quick

Mathematics
1 answer:
natulia [17]2 years ago
5 0

Answer:

I'm sorry I just need points!

Step-by-step explanation:

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Find the area. The figure is not drawn to scale.
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A = 1/2 b h where b = 3.4 cm and h = 8 cm

A = 1/2 (3.4)(8)

A = 13.6 cm^2

Answer: 13.6 cm^2

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A traffic consultant wants to estimate the true proportion of cars on a certain street that have more than two occupants. She st
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Answer:

The data is a simple random sample from the population of interest.

Step-by-step explanation:

Conditions necessary to consider when constructing a confidence interval include using a large sample size, which should be greater Than or equal to 30 for n and a sample proportion of np ≤ 10. Importantly the sample must be a random sample drawn from the population, meaning that all the population of interest must have equal chances of being a part of the sample data. However, the scenariomabiveb, violates this condition as the sampling design is not completely randomized. Those who do not ply the route on that certain day have no Chaves of being part of the sample.

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Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

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Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

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