The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take
1 answer:
Answer:
It will take <u><em>80 days</em></u> for the bull calf to reach a weight of 500 kilograms.
Step-by-step explanation:
Given:
The weight of a bull calf is 388 kilograms.
Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.
Required weight which to be increased = 500 - 388 = 112 kilograms.
Rate of weight increase =
=
Thus, the time required =
=
=
<em>The time required = 80 days</em>.
Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.
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Answer:
- B) One solution
- The solution is (2, -2)
- The graph is below.
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Explanation:
I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.
Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.
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To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,
y = (-3/2)x+1
y = (-3/2)*0+1
y = 1
The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.
Answer:
State A was the <u>12th</u> state to enter the Union. State B was the <u>11th</u> state to enter the Union.
Step-by-step explanation:
Let's call x to the order-of-entry of State B, therefore the order-of-entry of State A is x+1. Given that he product of their order-of-entry numbers is 132:
x*(x+1) = 132
x² + x - 132 = 0
Using quadratic formula:
The negative solution has no sense in the context of our problem, then the solution is x = 11.
<h2>☀️ <u>Solution</u><u>:</u></h2>
We all know that,
- All animals have 2 eyes.
- All cows have 4 feet
- All hens have 2 feet
So, Let the no. of cows be x and chickens be y
According to question,
- Total number of eyes = 162
Framing equation,
⇛ Eyes of cows + Eyes of chickens = 162
⇛ 2x + 2y = 162
⇛ 2(x + y) = 162
⇛ x + y = 162/2 = 81 -----------(1)
According to question(Cond.-1)
- Total number of feet = 270
Framing equation,
⇛ Feet of cows + Feet of chickens = 270
⇛ 4x + 2y = 270
⇛ 2(2x + y) = 270
⇛ 2x + y = 135 ----------(2)
Subtracting eq.(1) from eq.(2),
⇛ 2x + y - (x + y) = 135 - 81
⇛ 2x + y - x - y = 54
⇛ x = 54
Putting value of x in eq.(1),
⇛ 54 + y = 81
⇛ y = 81 - 54
⇛ y = 27
⚘ So, Total number of animals,
- Number of cows = x = 54
- Number of chickens = y = 27
Hence, solved !
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