No.
You may see it without computations: if 12 out of 20 doctors agree, it means that a bit more than half of the doctors agree (half of the doctors would be 10 out of 20).
In the second case, exactly half of the doctors agree, since 15 if the half of 30.
So, in the first case you have than more than half the doctors agree, while in the second case exactly half of the doctors agree.
Anyway, you can obviously perform more rigorous computations as well, and you have different methods available:
You can transform both ratios to have the same denominator:
And obviously
You can check the inequality by cross multiplying denominators:
You can convert fractions to decimal numbers:
Answer:
Step-by-step explanation:
Total number of laptops, N = 20
Defective laptops, n = 3
School purchase 2 laptops
Case 1:
Both laptops are non defective
Probability to choose 2 laptops which are non defective
Number of non defective laptops = 20 - 3 = 17
Total number of laptops = 20
Probability, P = 17/20 = 0.85
Case 2:
One laptop is defective
Probability to chose 1 defective and one non defective laptop
P' = 3/20 x 17/19 = 0.134
Case 3:
Both laptops are defective
Choosing of 2 laptops out of 3 = 3 C 2 = 3
choosing of 2 laptops out of 20 = 20 C 2 = 190
Probability of choosing two defective laptops = 3 / 190 = 0.0158
P'' =
Answer:
The probability that the sample mean is more than 110 is 0.0384.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (n > 30) are selected from the population with replacement, then the sampling distribution of the sample mean will be approximately normally distributed.
Then, the mean of the sampling distribution of sample mean is given by:
And the variance of the sampling distribution of sample mean is given by:
The information provided is:
Since <em>n</em> = 50 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the normal distribution.
The mean variance of the sampling distribution for the sample mean are:
That is, .
Compute the probability that the sample mean is more than 110 as follows:
*Use a <em>z</em>-table.
Thus, the probability that the sample mean is more than 110 is 0.0384.
Answer: The running speed of Elena is 5 miles/hour and this can be determined by using the formula of speed.
Step-by-step explanation:
A circular running track 1/4 is a mile long.
Elena runs on this track, completing each lap in 1/20 of an hour.
Speed formula is used to determine the speed of Elena. The formula of speed is given by:
----- (1)
where S is the speed, D is the distance and T is the time taken by Elena to run a circle.
Now, put the value of distance D and time T in the equation (1).
Speed = 5 miles/hour
Therefore, the running speed of Elena is 5 miles/hour.
For more information, refer to the link given below:
brainly.com/question/22610586
Answer:
33.6
Step-by-step explanation: