The relations are domain and range
<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
Answer:
3 and 12 students
Hope it helps
Step-by-step explanation:
Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.
Step-by-step explanation: Speed of Houck family's train = 552m/6hrs
speed of Robert family's train = 744m/8hrs.
Therefore considering Houck speed,
552miles = 6hours
1mile = (6 x 60)/552
= 360/552
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
For Robert
744miles = 8hours
1mile = ( 8 x 60 )/744
= (480/744)minutes
= 0.645
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
Conclusion: Both families were travelling at the same speed/rate.
To get that minutes in hour, just divide by 60 to get concert to hours.