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3 years ago

13

Help!

bsmiddle" class="latex-formula">
Thanks!

2 answers:

Kruka [31]3 years ago

4 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Here's the solution for You !

just combine the like terms :

$8r + 9 - 4r - 3r - 8r$

$- 7r + 9$

Harrizon [31]3 years ago

3 0

$\\ \sf\longmapsto 8r+9-4r-3r-8r$

$\\ \sf\longmapsto 8r-4r-3r-8r+9$

$\\ \sf\longmapsto -7r+9$

$\\ \sf\longmapsto 9-7r$

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Which expression has a value greater than 43 ?<br><br> PLEASEEE HELP!

lozanna [386]

Answer:

7^2

Step-by-step explanation:

7*7=49

4^3=43

49>43

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3 years ago

What is the value of y in the equation 2 + y = −3?

SOVA2 [1]

I believe that y is equal to -5.

y=-5

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3 years ago

Find the slope of the points: (-5,10)(-3,0)(0,1)(4,-4)

klasskru [66]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

-1/225x^2+2/3x what is the vertex of this quadratic function?

Julli [10]

$\bf \textit{vertex of a parabola}\\ \quad \\\\

\begin{array}{lccclll}
y=&-\frac{1}{225}x^2&+\frac{2}{3}x\\\\
y=&-\frac{1}{225}x^2&+\frac{2}{3}x&+0\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

6 0

3 years ago

The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the

erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter $\lambda=\frac{1}{\beta}=\frac{1}{19}$ .

The probability distribution function of <em>X</em> is:

$f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...$

Compute the value of the event (<em>X</em> > 14) as follows:

$P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786$

Thus, the probability that the wait time is greater than 14 minutes is 0.4786.

7 0

3 years ago