Y-y1=a(x-x1)
a=(y2-y1)/(x2-x1)
a= (6-(-2))/(7-1)
a=8/6
a=4/3
y-6=4/3(x-7)
y-6=4/3x-28/3
y=4/3x-28/3+6
y=4/3x-10/3 >>ef
It might be 8 hope this helped good luck on ur assignment
The answer is yes.
A line and a point outside the line define a unique plane. In other words, there is a single plane that contains a line and a point outside the line. If you are given line XY and point C outside the line, there is a single plane containing both line XY and point C. Therefore, line XY and point C must lie in the same plane.
I might not be understanding what you mean but I think it is by counting 10s. 170,180,190,200,210,220,230,240,250,260,270,280,290,300,310,320,330,410.