Can someone plss help me with this question!!
1 answer:
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Answer:
The mixture contains 80% water and 20% alcohol.
Step-by-step explanation:
Given:
Total Amount of mixture = 60 oz
Amount of alcohol in the mixture = 12 oz
We need to find the percentage of water and percentage of alcohol in the mixture.
Solution:
First we will find the amount of water in mixture.
Now we know that;
Total Amount of mixture is equal to sum of Amount of alcohol in the mixture and amount of water in mixture.
so we can say that;
amount of water in mixture = Total Amount of mixture - Amount of alcohol in the mixture
amount of water in mixture =
Now we will find the Percentage amount of water.
Percentage amount of water can be calculated by dividing amount of water in mixture by Total Amount of mixture and then multiplying by 100.
framing in equation form we get;
Percentage amount of water =
Percentage amount of alcohol =
Hence The mixture contains 80% water and 20% alcohol.
Hints on solving trigonometry problems:
If no diagram is given, draw one yourself.
Mark the right angles in the diagram.
Show the sizes of the other angles and the lengths of any lines that are known
Mark the angles or sides you have to calculate.
Consider whether you need to create right triangles by drawing extra lines. For example, divide an isosceles triangle into two congruent right triangles.
Decide whether you will need Pythagorean theorem, sine, cosine or tangent.
Check that your answer is reasonable. The hypotenuse is the longest side in a right triangle.
How to use the tangent ratio to find missing sides or angles?
Example:
