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White raven [17]
3 years ago
11

Find the slope and y-intercept. Also, determine if it is Proportional or Non Proportional

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

Answer:

Step-by-step explanation:

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is,

m = \frac{y_2-y_1}{x_2-x_1}

From the table attached,

Two points lying on the graph are (1, 12) and (2, 24).

Slope of the line will be,

m = \frac{24-12}{2-1}

Slope = 12

Since equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the line passing through (1, 12) and slope 12 will be,

y - 12 = 12(x - 1)

y = 12x - 12 + 12

y = 12x

By comparing this equation with the equation,

y = mx + b

where 'b' = y-intercept = 0

Since, y-intercept is zero, table will represent the proportional relation between x and y.

Proportional or non proportional → Proportional

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2 years ago
Help me please thank you.
jenyasd209 [6]
The correct answer is A: 2.

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2 years ago
Sistema de ecuaciones.5x+2y=-152x-2y=-6
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Tnemos el sisema de ecuaciones:

\begin{gathered} 5x+2y=-15 \\ 2x-2y=-6 \end{gathered}

Podemos resolverlo por eliminación sumando ambas ecuaciones y eliminando y. Asi podemos resolver para x:

\begin{gathered} (5x+2y)+(2x-2y)=(-15)+(-6) \\ 7x+0y=-21 \\ x=-\frac{21}{7} \\ x=-3 \end{gathered}

Ahora podemos resolver para y con cualquiera de las dos ecuaciones:

\begin{gathered} 2x-2y=-6 \\ 2\cdot(-3)-2y=-6 \\ -6-2y=-6 \\ -2y=-6+6 \\ -2y=0 \\ y=0 \end{gathered}

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