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julsineya [31]
3 years ago
6

Solve V = 1/3(3.14)r^2h for h

Mathematics
2 answers:
Ber [7]3 years ago
7 0
<span>V = 1/3(3.14)r^2h
=1.046r^2h

Solving for V </span>
Oksi-84 [34.3K]3 years ago
3 0
V=1.046r2h

With a mine over the 6
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1.9 An electronics store buys media from customers
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The store pays $2 for each Blu-ray disc, $0.75 for each DVD, and

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Step-by-step explanation:

An electronics store buys media from customers  to resell.

The given is:

1. The store pays one customer $5.30 for one  Blu-ray disc, four DVDs,

   and three VHS cassettes

2. The store pays the second customer $11.50 for five Blu-ray discs

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3. The store pays the third customer $10.20 for two Blu- ray discs, eight

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We need to find the amount the store pays for each item

Assume that:

The cost of a Blue-ray disc is $x

The cost of a DVD is $y

The cost of a VHS cassette is $z

∴ x + 4y + 3z = 5.3 ⇒ (1)

∴ 5x + 2y = 11.5 ⇒ (2)

∴ 2x + 8y + 2z = 10.2 ⇒ ÷ 2

∴ x + 4y + z = 5.1 ⇒ (3)

- Subtract equation (3) from equation (1)

∵ x + 4y + 3z = 5.3 ⇒ (1)

∵ x + 4y + z = 5.1 ⇒ (3)

∴ 2z = 0.2

- Divide both sides by 2

∴ z = 0.1

Substitute the value of z in equation (3)

∴ x + 4y + 0.1 = 5.1

- Subtract 0.1 from both sides

∴ x + 4y = 5 ⇒ (4)

Let us solve equations (2) and (4)

∵ 5x + 2y = 11.5 ⇒ (2)

∵ x + 4y = 5 ⇒ (4)

- Multiply equation (2) by -2 to eliminate y

∴ -10x - 4y = -23 ⇒ (5)

- Add equations (4) and (5)

∴ -9x = -18

- Divide both sides by -9

∴ x = 2

- Substitute the value of x in equation (2)

∴ 5(2) + 2y = 11.5

∴ 10 + 2y = 11.5

- Subtract 10 from both sides

∴ 2y = 1.5

- Divide both sides by 2

∴ y = 0.75

The store pays $2 for each Blu-ray disc, $0.75 for each DVD, and

$0.1 for each VHS cassette

Learn more:

You can learn more about solving equations in brainly.com/question/9045597

#LearnwithBrainly

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During the assembly of a certain piece of exercise equipment, 3 welds are required during different phases of the assembly proce
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Answer:

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This is a binomial probability distribution.

Since the probability of satisfactory welds = 97% = 0.97 and the probability of defective welds = 3% = 0.03.

Since there are 3 welds and we require at least one being defective, our binomial probability is

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5 0
3 years ago
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