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2 years ago

Find three quarters of a tenth of 800

1 answer:

4 0

Answer is 60

Step by step

Your equation
3/4 of 1/10 of 800 = n

Factor out common factors and multiply, see attached work sheet

Or

You can change fractions into decimals and multiply on your calculator

.75 x .10 x 800 = 60

60 = n

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Hey Everyone I was asking anyone can help with this problem it would really appreciated.

posledela

Answer:

angle G = angle I

HGI=HIJ by RHS fact

HGI=HIJ corresponding angles are alwyas congurrent

6 0

3 years ago

What is the rate of change of the function y = 7/4x+1?

Leokris [45]

Answer:

7/4!

Step-by-step explanation:

I think?

6 0

3 years ago

Compare the decimals 56.07 and 56.7. Which comparison is correct? A. 56.07 > 56.7 B. 56.07 = 56.7 C. 56.07 < 56.7

Mice21 [21]

C. 56.07 < 56.7 could be right.

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28%20-%20%2055%292" id="TexFormula1" title="( - 55)2" alt="( - 55)2" align="absmiddle" clas

Art [367]

The answer is -110.
This is because -55-55=-110.
You have to put -55-55 because the question is asking for you to multiply -55 twice, which is technically-55-55.

8 0

3 years ago

Read 2 more answers

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }$ and a bit more to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }$

Bring up the lower fraction and flip it to divide to get

$tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1}$ which of course simplifies to

-3. Choice A.

6 0

3 years ago