All categories

3 years ago

What is the formula for the circumference using the radius below?

Mathematics

1 answer:

Nat2105 [25]3 years ago

7 0

Answer:

2π(5)

Step-by-step explanation:

Circumference

C=2πr

You might be interested in

Suppose that each semester at a particular community college Manuel has to pay $1478 in tuition and $121 in fees.

Kamila [148]

Answer:

Step-by-step explanation:

Let x be time, in semesters, remaining before Manuel graduates. We find that Manuel's expenses are:

$1478/semester in tuition, and

$121/semester in fees

1. x semesters remaining: fees

Remaining cost for fees, y, is the product of the fee times the number of semesters, x:

y =($121/semester)*x

y = ($121)*x

2. x semesters remaining: tuition

Remaining cost, y, is the product of the tuition (times the number of semesters, x.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

3. x semesters remaining: tuition and fees

Remaining cost, y, is the sum of the products of the tuition (times the number of semesters, and the fees (tix.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

5 0

1 year ago

Which sampling would be appropriate to survey 120,000 people?

kipiarov [429]

Answer: Id say b

Step-by-step explanation: a would be too high and a bit too detailed. Whereas c and d will be inaccurate.

8 0

3 years ago

Find the maximum and minimum value of: 1/X plus 3x root X plus root (4-x)

Eddi Din [679]

Evet hocam proje konularını da bir bir insan değilim ki bir uyu bir insan bir arar bir insan bir şey var

7 0

3 years ago

X = sin 1/2θ, y = cos 1/2θ, −π ≤ θ ≤ π(a) eliminate the parameter to find a cartesian equation of the curve.

Roman55 [17]

First solve for theta in 'x' equation:
$\theta = 2 sin^{-1} x$

Substitute into 'y' equation:
$y = cos (\frac{2 sin^{-1} x}{2}) = cos (sin^{-1} x)$

Simplify by rewriting cos in terms of sine.
Using pythagorean identity: $sin^2 + cos^2 = 1$

$cos = \sqrt{1-sin^2} \\ \\ y = \sqrt{1-sin^2 (sin^{-1} x)}$
Simplify using inverse function property: $f(f^{-1} (x)) = x$

$y = \sqrt{1 - x^2}$

5 0

3 years ago

Read 2 more answers

Solve the following system. y = x 2 - 9x + 10 and x + y + 5 = 0. The solutions are

shepuryov [24]

X+y+5=0

y=-x-5

If a solution exists y=y so we can say

x^2-9x+10=-x-5 add x+5 to both sides

x^2-8x+15=0 now factor

x^2-3x-5x+15=0

x(x-3)-5(x-3)

(x-5)(x-3) so x=3 and 5, using y=-x-5

y(3)=-8 and y(5)=-10

So the two solutions are:

(3,-8) and (5,-10)

6 0

3 years ago

Read 2 more answers