ramone has 5 difficult questions left to answer on a multiple choice test. Each question has 3 choices. For the first 2 of these
questions, he eliminated 1 of the 3 choices. find the probability that he will answer the first 2 questions, as well as at least 2 of the 3 remaining questions correctly.
then she eliminated 1 choice in 1 and 2, say as follows
1. b c 2. a b 3. a b c 4. a b c 5. a b c
Probability of answering correctly the first 2, and at least 2 or the remaining 3 is P(answering 1,2 and exactly 2 of 3.4.or 5.)+P(answering 1,2 and also 3,4,5 )
P(answering 1,2 and exactly 2 of 3.4.or 5.)= P(1,2,3,4 correct, 5 wrong)+P(1,2,3,5 correct, 4 wrong)+P(1,2,4,5 correct, 3 wrong) also P(1,2,3,4 c, 5w)=P(1,2,3,5 c 4w)=P(1,2,4,5 c 3w ) so P(answering 1,2 and exactly 2 of 3.4.or 5.)=3*P(1,2,3,4)=3*1/2*1/2*1/3*1/3*2/3=1/4*2/9=2/36=1/18
Okay so first of all we need to know the definition of our median first* median: Given any group of numbers we put the numbers in order from least to greatest then find the number that's right in the middle. Here ill show you how we do it:) <span>3.60, 3.80, 5.44, 5.52, 5.72, 7.22? its already in order for us:) but when we find the middle number it turns out that we have two middle numbers:/ simple:) all we do is take the two numbers add them together and divide by two since our middle numbers are 5.44 and 5.52 we are going to use these:) first add! 5.44 + 5.52 = 10.96 now divide that by 2 10.96 </span>÷ 2 = 5.48 so our median for this set of numbers is 5.48! hope this helps;)
