at time t=0 particle is projected with a velocity of 2 i m/s from point with position vector ( 10i + 90j ) m/s . the position ve
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Answer:
x ≈ - 9.41, x ≈ - 6.59
Step-by-step explanation:
Given
x² + 16x + 62 = 0 ( subtract 62 from both sides )
x² + 16x = - 62
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(8)x + 64 = - 62 + 64
(x + 8)² = 2 ( take the square root of both sides )
x + 8 = ± ( subtract 8 from both sides )
x = - 8 ±
Hence
x = - 8 - ≈ - 9.41
x = - 8 + ≈ - 6.59
To solve for x in the given equation;
We start by collecting like terms, as follows;
When a number crosses the sign of equality, the sign in front of it switches. Positive numbers becomes negative, and vice versa.
We would now have;
ANSWER:
The answer is x = -8