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3 years ago

For the polynomial f(x) = 3x^3 + 3x^2 - 13x + 12 determine the average rate of change between the two given values for x

Mathematics

1 answer:

AnnyKZ [126]3 years ago

4 0

Answer:

Well plz dont delete my question I need points to get mine out

Step-by-step explanation:

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What is the calculation for determining simple interest and compound interest? Borrowing if borrowed $20,000 for 5 years at a 4%

yarga [219]

Answer:

If using simple interest, the formula is:

= Amount * ( 1 + rate * time)

= 20,000 * ( 1 + 4% * 5)

= $24,000

Interest = Balance after 5 years - Investment

= 24,000 - 20,000

= $4,000

Using Compound Interest:

= Amount * ( 1 + rate)^time

= 20,000 * ( 1 + 4%)⁵

= $24,333.06

Interest = 24,333.06 - 20,000

= $4,333.06

6 0

3 years ago

Oh mah lord please please help me

Alenkinab [10]

Option 2: $4^{\frac{1}{6}}$ is the correct answer.

Step-by-step explanation:

The radical expressions like these are simplified by using fractional exponents

given

$\frac{\sqrt{4}}{\sqrt[3]{4} }$

Converting radicals into exponents

When there is no base the exponent is 1/2 and as the base is 3, the exponent will be 1/3

$=\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}$

As the bases of numerator and denominator is same, the exponents can be subtracted

$=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}$

Hence,

Option 2: $4^{\frac{1}{6}}$ is the correct answer.

Keywords: Exponents, radicals

Learn more about radicals at:

#LearnwithBrainly

7 0

3 years ago

The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of

ivanzaharov [21]

<h2>Answer:</h2>

$R_2$ is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors $R_1$ and $R_2$ connected together in parallel, the total resistance $R_T$ is given by;

$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}$ ---------(i)

<em>Make </em> $R_2$ <em> subject of the formula;</em>

=> $\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}$

=> $\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}$

=> ${R_2} = \frac{R_TR_1}{R_1 - R_T}$ ---------------(ii)

From the question,

$R_1$ = 6Ω

$R_T$ = 2Ω

Substitute these values into equation (ii) as follows;

=> ${R_2} = \frac{2*6}{6 - 2}$

${R_2} = \frac{12}{4}$

$R_2$ = 3Ω

Therefore, the value of $R_2$ = 3 ohms or $R_2$ = 3Ω

3 0

3 years ago

PLEASE HELP!!!! Find the area of the rhombus.

anygoal [31]

Answer:

Step-by-step explanation:

A=pq

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6 0

2 years ago

Read 2 more answers

Picture attached, please simplify

Charra [1.4K]

The answer is the second option given

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3 years ago