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olya-2409 [2.1K]
3 years ago
13

Write a formula for quadratic function if its graph has the vertex at point (−2,5) and passes through the point (3,−10).

Mathematics
1 answer:
Furkat [3]3 years ago
8 0

Answer:

The formula for the quadratic function is y=5 - \frac{3}{5} \left(x + 2\right)^{2}.

Step-by-step explanation:

The quadratic function with vertex (h,k) is given by y=a \left(- h + x\right)^{2} + k.

We know that the vertex is (-2,5). Thus, the formula for the quadratic function is

y=a \left(x + 2\right)^{2} + 5

To find a, use the fact that the quadratic function passes through the point \left(3, -10\right) and we solve for a.

-10=a \left(3 + 2\right)^{2} + 5\\a\left(3+2\right)^2+5=-10\\5^2a+5=-10\\25a+5=-10\\25a=-15\\\frac{25a}{25}=\frac{-15}{25}\\a=-\frac{3}{5}

Thus, the formula for the quadratic function is y=5 - \frac{3}{5} \left(x + 2\right)^{2}.

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B completes the line bc it goes 1 2 3 4 then 5
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3 years ago
Two Fifths of the vegetables in Priya's garden are tomatoes.
IgorLugansk [536]
Let
V-------------> total <span>vegetables in Priya's garden
T------------> total tomatoes </span>in Priya's garden

we know that
T=(2/5)V

Part A) <span>HOW many tomatoes are there I'd Priya's garden has.

1) </span><span>20 Vegetables?
</span>T=(2/5)*20----------> 20*2/5---------> 8 tomatoes
<span>the answer Part A1) is 8 tomatoes
</span>
2) x Vegetables?
T=(2/5)*x----------> x*2/5---------> (2/5)*x  ----------> 0.40*x tomatoes
the answer Part A2) is (0.40)*x  tomatoes

Part B) <span>Priya's garden has 6 tomatoes. How many total vegetables are there?

</span>T=(2/5)V-----------> V=5T/2--------> V=(5*6)/2--------> V=15 vegetables
<span>
the answer part B) is </span>15 vegetables<span>

</span>
5 0
3 years ago
a rectangular picture 16 inches by 20 inches has a frame of uniform width. Find the width of the frame if the total area of the
lianna [129]

Answer: 22

Step-by-step explanation:

The area of the picture =l×b = 20×16=320

The length of the frame is 16

If the width is x ( and it's uniform)

672- 320= 352

Area of the frame = 16× x=352

x=352/16

x = 22

7 0
4 years ago
Do the following lengths form a right triangle? (Also how to tell that they do form a right triangle)
ololo11 [35]

Answer: Yes this is a right triangle

We can determine this by using the converse of the pythagorean theorem.

a = 5, b = 12, c = 13

a^2 + b^2 = c^2\\\\5^2 + 12^2 = 13^2\\\\25 + 144 = 169\\\\169 = 169 \ \ \checkmark\\\\

Since those a,b,c values work in the pythagorean theorem, this proves we have a right triangle.

4 0
2 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
HACTEHA [7]

Answer:

(a) The value of P (X ≤ 2) is 0.8729.

(b) The value of P (X ≥ 5) is 0.0072.

(c) The value of P (1 ≤ X ≤ 4) is 0.7154.

(d) The probability that none of the 25 boards is defective is 0.2774.

(e) The expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defective boards.

The probability that a circuit board is defective is, <em>p</em> = 0.05.

The sample of boards selected is of size, <em>n</em> = 25.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={25\choose x}0.05^{x}(1-0.05)^{25-x};\ x=0,1,2,3...

(a)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

P(X\leq =x)=\sum\limits^{2}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.2774+0.3650+0.2305\\=0.8729

Thus, the value of P (X ≤ 2) is 0.8729.

(b)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = 1 - P (X < 5)

              =1-\sum\limits^{4}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=1-0.9928\\=0.0072

Thus, the value of P (X ≥ 5) is 0.0072.

(c)

Compute the value of P (1 ≤ X ≤ 4) as follows:

P (1 ≤ X ≤ 4) = P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

                   =\sum\limits^{4}_{x=1}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.3650+0.2305+0.0930+0.0269\\=0.7154

Thus, the value of P (1 ≤ X ≤ 4) is 0.7154.

(d)

Compute the value of P (X = 0) as follows:

P(X=0)={25\choose 0}0.05^{0}(1-0.05)^{25-0}=1\times 1\times 0.277389=0.2774

Thus, the probability that none of the 25 boards is defective is 0.2774.

(e)

Compute the expected value of <em>X</em> as follows:

E(X)=np=25\times 0.05=1.25

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{25\times 0.05\times (1-0.05)}=1.09

Thus, the expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

8 0
4 years ago
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