Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
The area of a parallelogram is base times height. Each side can be a base, and has a particular height associated with it.
Here the height associated with the 1.5 base is 2.7, and the height associated with the 3.6 base is h. So
Answer: 1.125 units
Answer:
y = 1x + 46
Step-by-step explanation:
9514 1404 393
Answer:
-7x^2 +8x -10
Step-by-step explanation:
Combine like terms in the usual way.
(-3x^2 +5x -8) -(4x^2 -3x +2)
= -3^2 +5x -8 -4x^2 +3x -2
= (-3-4)x^2 +(5+3)x +(-8-2)
= -7x^2 +8x -10