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N76 [4]
3 years ago
11

Solve x: (On the attachment) Please Help! Homework due in for tomorrow! Xx

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
8 0

x-3 / 4 -2 = -9

Add 2 to each side:

x-3 /4 = -7

Multiply each side by 4:

x-3 = -28

Add 3 to each side:

x = -25

OleMash [197]3 years ago
3 0
Hey the answer is -25
Hope this helps pls mark as brainliest answer plsssssssssssssssssssss
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Let f(x)=18/1+3^e-0.1x What is the point of maximum growth rate for the logistic function f(x)? Show all work. Round your answer
xz_007 [3.2K]

Answer:

(0, 4.5)

Step-by-step explanation:

*The equation can be put into Desmos, to find the point, but the work to prove it is here*

f(x)=c/1+Ae^-Bx

Y=C

C=18      A=3      -B=-0.1

*Replace x with 0 in the equation, so you know 0 is the x value, and it leads you to the y value*

f(0)=18/1+3e^-o.1(0)

= 18/1+3e^0

=18/1+3(1)

=18/1+3

=18/4

=4.5

x=0    y=4.5

Maximum growth rate = (x,y) --> (0, 4.5)

Hope this helps:))!!

5 0
3 years ago
Evaluate if m = 16 and p = 2. 1/2m + 3p
Lunna [17]

Answer is 14

EXPLANATION:

(1/2)(16)+(3)(2) =

8+6 =

14

3 0
3 years ago
Deer ticks can be carriers of either Lyme disease or human granulocytic ehrlichiosis (HGE). Based on a recent study, suppose tha
san4es73 [151]

Answer:

0.2364

Step-by-step explanation:

We will take

Lyme = L

HGE = H

P(L) = 16% = 0.16

P(H) = 10% = 0.10

P(L ∩ H) = 0.10 x p(L U H)

Using the addition theorem

P(L U H) = p(L) + P(H) - P(L ∩ H)

P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)

P(L U H) = 0.26 - 0.10p(L u H)

We collect like terms

P(L U H) + 0.10P(L U H) = 0.26

This can be rewritten as:

P(L U H)[1 +0.1] = 0.26

Then we have,

1.1p(L U H) = 0.26

We divide through by 1.1

P(L U H) = 0.26/1.1

= 0.2364

Therefore

P(L ∩ H) = 0.10 x 0.2364

The probability of tick also carrying lyme disease

P(L|H) = p(L ∩ H)/P(H)

= 0.1x0.2364/0.1

= 0.2364

3 0
3 years ago
??????????????????????
ale4655 [162]

Answer:

Area = 58 \ units^2

Step-by-step explanation:

We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:

a^2+b^2=c^2

In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:

3^2+7^2=c^2

9+49=c^2

c^2=58

c=\sqrt{58}

Since the area of a square is the side length square then...

Area =( \sqrt{58} )^2

The square root and the squared cancel out giving us...

Area = 58 \ units^2

3 0
3 years ago
Help me please. I’m dying of frustration
KiRa [710]

I've answered this before, but only partially. I'm not sure about the second part, but I think the first one is 10

4 0
3 years ago
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