In a triangle, the nomenclature is that a variable side a is opposite of the angle A. we can use the cosine law to determine the value of cosine A.
a2 = b2 + c2 -2bc cos a25 = 36 + 64 - 2*6*8 * cos acos a = 25/32
The answer is A = P²/16
The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²
Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.
Step 1:
P = 4s
s = P/4
Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
Answer:
the correct answer is -16
Step-by-step explanation:
I took the test
(-5,-8)
The coordinates are still the same because a rotation of 360° is a complete circle, therefore the points remain in the same spot.
