Answer:
40.5
Step-by-step explanation:
there are 4 laps in 200 metres.
(200m÷50m)
2min 42 sec=120 sec+42sec (162sec)
so,
162÷4=40.5
498 is approximately 500
12 is approximately 10
500/10 = 50
So, 498/12 is approximately 50.
2 × c ÷ 7 ÷ 2. This better?
Answer:
Ground speed = 131.25 km/h
Bearing = 92.68º
Step-by-step explanation:
If we imagine a triangle to depict the question with one side 134 km/h at an angle of 78º to the right of vertical (the plane's speed vector).
At the end, we have a line 21 km/h at an angle of 180 (from north), a vertical down from the end of the plane's vector. This vertex is angle B
This makes a triangle with the interior angle B of 78º.
The 3rd side is the ground speed which we can find using the Cosine rule:
b² = a² + c² - 2•a•c•cos(78)
b² = 134² + 21² - 2•134•21•cos(78)
b² = 17226.873
b = 131.25 km/h
The true course bearing" is the ground track. Thus;
Using the Sine rule to find angle A, we have;
(sin(A))/34= sin(78)/b
Thus,
sin(A) = (34 x sin(78))/131.25
sin(A) = 0.2534
A = sin^(-1)0.2534
A = 14.68º
Ground track = A + 78 = 14.68 + 78 = 92.68º
7x + 7y = -21
48x - 8y = 136 This is where you find a common sum.
8(7x + 7y = -21) ex: 7 and 8
7(48x - 8y = 136)
56x + 56y = -168 Multiply it out
336x -56y = 952
392x = 784 Divide/Simplify
x = 2
Now substitute to find Y. I hope this helped!
