If x > 0 then |x|/x = 1 !!!
If x<0 then |x|/x = -1
*below is an explanation! :)
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- I found the answer to this by choosing a any number that satisfies the requirement of x > 0 and plugging it into |x|/x
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Watch this!
Let's take 10 for example. 10 is greater than 0 like x>0 requires!
Let's plug it into |x|/x
|10| ÷ 10 = 1
*Remember that | | this means "absolute value" or whatever is in between the two bars will always be positive (+)
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Now let's take a random number that satisfies 0> x and do the same as we did above!
Let's take -3 and plut it into |x|/x
|-3| ÷ -3 = -1
Answer:
(a) [8, 14]
(b)
(c)See attachment
Step-by-step explanation:
We want to choose a value of x within 3 units of 11.
(a)Now, 11-3=8 and 11+3=14
The possible values of x ranges is in the closed interval [8,14]
(b) Since x is within 3 units of 11., we have:
Solving the absolute inequality
(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.
Answer:
x+2
Step-by-step explanation:
replace ab with x