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Semmy [17]
3 years ago
6

What is the y value of the line when x = -1

Mathematics
1 answer:
sveticcg [70]3 years ago
6 0
I cannot answer that question because I need to equation
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Find the average rate of change from x = 3 to x = 15 for the function f(x) = 0.01(2)x
julsineya [31]
The average rate of change for this is the slope of the secant line that connects those 2 points (3, y) and (15, y).  What we need for the slope formula of change in y over change in x are the y values which are unknown as of right now. We can find them though! Don't worry! The equation is y = .01(2)^x. Using that equation, let's sub in both the 3 and the 15 and find the corresponding y values. Subbing in first a 3 gives you y = .01(2)^3, and y = .08.  Subbing in a 15 gives you y = .01(2)^15 and y = 327.68. Now we have the coordinates we need to find the slope of the secant line connecting those 2 points: (3, .08) and (15, 327.6). Fitting those into the slope formula gives us (327.68-.08)/(15-3). Simplifying that is 327.6/12 which divides out to 27.3
3 0
3 years ago
HELP PlS ASAP
Anarel [89]

Answer:

The correct answer is option B.

Step-by-step explanation:

Two point form of the equation:

A line passing through the point (-1,6) with slope ,m = -3.

The equation of the line will be: y-6= (-3)(x-(1))=(-3)(+1)

3 0
2 years ago
4 + 2x - 7 = 12<br><br> ?????
Rainbow [258]

Answer:

15/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

                              P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0

Thus,

                                    Q_x -P_y = 0 -2 = - 2

Now, by the Green's theorem, we have

\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x  \Big|_{-3}^{4} = -42

4 0
3 years ago
-36.12 divided by -5 3/5
Nataliya [291]
<h3 /><h3>- 36.12 \div  - 5 \frac{3}{5}  \\  - 36.12 \div  -  \frac{28}{5}  \\  = 6.45</h3>

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

5 0
2 years ago
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