The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
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The answer is: c
Explination 30-9=21
Answer:
<2 = 121
Step-by-step explanation:
Consecutive exterior angles add up to 180 degrees.
Basically the real one is 80 times the picture
80 times 3/4=80/1 times 3/4=240/4=60in=5ft
it is 5ft long or 60in
Answer:
A quadratic equation is some thing like
(x+2)^2
or
(x+2)(x+5)
In order to solve them, the most basic method is the FOIL method
F-First
O-Outside
I-Inner
L-Last
So for example
(x+2)^2
Which is basically
(x+2)(x+2)
So the first is the 2 Xs
(x+2)(x+2)
x*x=x^2
The outer is the x and the 2,
(x+2)(x+2)
2*x=2x
Now the Inner which is the 2 and the x
(x+2)(x+2)
2*x=2x
And finally the last which is the 2 and the second 2
(x+2)(x+2)
2*2=4
Now add them all up
X^2+2x+2x+4
Combine like terms
x^2+4x+4
There you have it
Do the same with every other quadratic equation
