Answer:
The equation of the line is:
Step-by-step explanation:
The slope-intercept form of the line equation
y = mx+b
where
Given
now substituting b = -12 and m = 3/2 in the slope-intercept form of line equation
Therefore, the equation of the line is:
3p + 34 = 90
3p = 90 - 34
3p = 56
p = 56/3
p = 18.67 (thats rounded)
2r + 44 = 76
2r = 76 - 44
2r = 32
r = 32/2
r = 16
53 + 6s = 1421
6s = 1421 - 53
6s = 1368
s = 1368/6
s = 228
" the product " means multiply
p x r x s = 18.67 x 16 x 228 = 68,108.16
10x + 5 = 16x - 1
<span>6x = 6 </span>
<span>x = 1 </span>
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
The answer is <span>A) none of the situations
~ if you can, would you give me the brainlyest? Thanks and have a good day! :D
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