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irga5000 [103]
3 years ago
15

What’s the converse of the statement???

Mathematics
1 answer:
BARSIC [14]3 years ago
5 0
B would be the answer
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Pls help! will give brainlist!
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It couldn’t be anything else but C line reflection i’m assuming
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The Kendal Company manufactures automobile engine parts. Running the manufacturing operations requires 12 watts (units of electr
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A figure has vertices at L(3,3), M(2,4), and N(−1,0). After a transformation, the image of the figure has vertices at L′(2,−5),
alexandr402 [8]

The transformation was a reflection over the line x = -0.5

And the image and preimage can be seen in the graph below.

<h3>How to identify the preimage and image?</h3>

First, the original vertices are:

L(3, 3)

M(2, 4)

N(-1, 0)

3 vertices means that our figure is a triangle.

Now, the transformed vertices are:

L'(2, -5)

M'(3, -4)

N'(-1, 1)

And the graph of both sets can be seen below.

Now we can try to identify the transformation.

Now, notice that all the points (L, M, N, L', N', M') are equidistant to the horizontal line x = -0.5

This is a clear implication that the transformation was a reflection over the line x = -0.5

If you want to learn more about transformations:

brainly.com/question/4289712

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3 0
1 year ago
For which function is f(x) equal to f^1(x) ( answer choices in picture )
Sonja [21]

Answer:

C. f(x)=\frac{x+1}{x-1}

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+6}{y-6}

Rewrite in terms of 'y'. This gives,

x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}

The given function y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}

So, option A is incorrect.

Option B:

f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+2}{y-2}

Rewrite in terms of 'y'. This gives,

x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}

The given function y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}

So, option B is incorrect.

Option C:

f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+1}{y-1}

Rewrite in terms of 'y'. This gives,

x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}

The given function y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}

So, option C is correct.

Option D:

f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+5}{y-5}

Rewrite in terms of 'y'. This gives,

x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}

The given function y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}

So, option D is incorrect.

Therefore, only option C is correct.

7 0
3 years ago
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