Answer:
70°, 140°, 50°
Step-by-step explanation:
110° and the angle inside the triangle are adjacent angles and sum to 180°, so
angle inside triangle = 180° - 110° = 70°
The triangle on the left is isosceles ( 2 congruent sides ) then base angles are congruent
∠ 1 = angle inside triangle = 70°
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ 2 is an exterior angle of the triangle on the left, so
∠ 2 = 70° + 70° = 140°
∠ 2 is also an exterior angle of the triangle on the right, so
∠ 3 + 90° = 140° ( subtract 90° from both sides )
∠ 3 = 50°
X=moira y=mother
x=1/2y-3
x=1/2(76)-3
x=38-3
x=35
Moira is 35 years old.
Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

Class
Interval Midpoints
45-48 
49-52 
53-56 
57-60 
61-64 
65-68 
69-72 
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5
I believe the answer is correct