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jeka94
3 years ago
14

Where is the blue dot on the number line? (please hurry!)

Mathematics
2 answers:
ser-zykov [4K]3 years ago
5 0

Answer:

-0.58

Step-by-step explanation:

Each division is 1/100  or 0.01

-(0.55 + 0.01) = - 0.56

-(0.56 +0.01) = -0.57

-(0.57 + 0.01) = -0.58

Hoochie [10]3 years ago
4 0

Answer:

The point is at -0.58

Step-by-step explanation:

If you count each line, they each represent 0.1, so -0.55, -0.56, -0.57 and -0.58 is the 4th line

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40 POINTS!
spayn [35]

Answer:

70°, 140°, 50°

Step-by-step explanation:

110° and the angle inside the triangle are adjacent angles and sum to 180°, so

angle inside triangle = 180° - 110° = 70°

The triangle on the left is isosceles ( 2 congruent sides ) then base angles are congruent

∠ 1 = angle inside triangle = 70°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 2 is an exterior angle of the triangle on the left, so

∠ 2 = 70° + 70° = 140°

∠ 2 is also an exterior angle of the triangle on the right, so

∠ 3 + 90° = 140° ( subtract 90° from both sides )

∠ 3 = 50°

7 0
2 years ago
PLEASE HELP:
Tema [17]
X=moira y=mother

x=1/2y-3 

x=1/2(76)-3

x=38-3

x=35  

Moira is 35 years old.
3 0
3 years ago
Simplify 9 - {x - (7 + x)}.
LekaFEV [45]

9 - (x - 7 - x) \\ 9 - ( - 7) \\ 9 + 7 \\  = 16
4 0
3 years ago
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
Os ths the answer 19×6=114
SSSSS [86.1K]
I believe the answer is correct
5 0
4 years ago
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