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Fittoniya [83]
2 years ago
15

MONEY Gillian, Roger, LaToya, and Ichiro had lunch at a restaurant. After sales tax and tip were added, the total bill was $23.8

0. They decided that everyone would pay 25% of the total bill. What is a reasonable amount for how much each person paid?
Mathematics
1 answer:
leonid [27]2 years ago
5 0

Answer:

23.80/100 X 25 = 5.95

they each paid $5.95

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PLEASE HELP<br> Complete the table by computing the amount in the account at the end of each period.
skad [1K]

Answer:

See below

Step-by-step explanation:

  • Initial Principal P₀ = 1000
  • End of first period = 1000 + 1000*0.02/4 = 1005
  • End of second period = 1005 + 1000*0.02/4 = 1010
  • End of third period = 1010 + 1000*0.02/4 = 1015
  • End of fourth period = 1015 + 1000*0.02/4 = 1020

8 0
3 years ago
Someone please help me I really need help !!!!
DanielleElmas [232]

Answer:

\frac{71}{100}

<h3>Answer c</h3>

Step-by-step explanation:

\frac{14}{100}  = squash \\  \frac{3}{20}  =  \frac{15}{100}  = tennis \\  \frac{14 +1 5}{100}  =  \frac{29}{100}  \\  \\  \frac{100}{100}  -  \frac{29}{100  }  \\  =  \frac{71}{100} = rugby

5 0
2 years ago
Easy Multiple Choice Questions about expressions and linear equations / ASAP / Will mark brainliest / 25 Points
nata0808 [166]

Answer:

1.C

2.A

3.D

4.C

5.B

6.A

7.B

8.C

9.A

10. D

Step-by-step explanation:

For Problem 1, the work is as follows:

2(3x-1)+x\\Distribute\\6x-2+x\\7x-2

For Problem 2, the work is as follows:

(3x^{2} +6x+4) - (-x^{2} +2x-1)\\Distribute -\\(3x^{2} +6x+4) + (x^{2} -2x+1)\\Combine\\4x^{2} +4x+5

For Problem 3, the work is as follows:

5b-(a+c)^{2} \\5(3) - (-1+-4)^{2} \\15 - (-5)^{2} \\15-25\\-10

For Problem 4, the work is as follows:

4x-8 = -12\\+8\\4x = -4\\-4/4 = -1\\x = -1

For Problem 5, the work is as follows:

\frac{1}{2} (12x-6) = 2x-15\\Distribute\\\\6x - 3 = 2x -15\\+3\\6x = 2x -12\\-2x\\4x = -12\\-12/4\\x = -3

For Problem 6, the work is as follows:

17 *0.06 = 1.02\\17+1.02 = 18.02

For Problem 7, the work is as follows:

x = (2,0)\\y = (0,-1)\\\frac{rise}{run} \\y = \frac{1}{2} x-1

For Problem 8, the work is as follows:

y_{2} -y_{1} \\x_{2} -x_{1} \\-1-1 = -2\\0-(-2) = 2\\Slope = -1

For Problem 9, the work is as follows:

3y - 2x +6 = 0\\-3y\\(-3y - -2x+6)/-3\\y = \frac{2}{3} x -2

For Problem 10, the work is as follows:

(y-3) = -2(x-1)\\Distribute\\(y-3) = -2x+2\\+3\\y = -2x +5

Hope this Helps!

4 0
3 years ago
Draw a conclusion is the statement below always sometimes or never true give at least two examples to support your reasoning the
hodyreva [135]
It's sometimes true.

One example is the least common multiple of 2 and 3 is 6, which is their product.

But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.

Ergo, it is only sometimes true.
3 0
3 years ago
0.08 is 10 times grater than
solong [7]
Subtract the minimum data value from the maximum data value to find the data range,so in this case yur data range is 

10 - 0.08 = 9.92
so yur answer is 9.92
4 0
2 years ago
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