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True [87]
3 years ago
5

Which one of these four sets of side lengths will form a right triangle?

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0

Answer:

Option B is the answer.

Step-by-step explanation:

We know in a right angle triangle when we apply Pythagoras Theorem, then

(Hypotenuse)² = ( side 1)² + (side 2)²

(A) set (1) ⇒ 6 cm, 7 cm, √12 cm

7² = 6² + (√12)²

49 = 36 + 12 = 48

49 ≠ 48     Therefore, its not the sides of a right triangle.

(B) Set (2) ⇒ 8 in, √29 in, √35 in

                    8² = (√29)² + (√35)²

                  64 = 29 + 35

                   64 = 64    So its a right angle triangle

(C) Set (3) ⇒ √3 mm, 4 mm √5 mm

         4² = (√3)² + (√5)²

         16 = 3 + 5

         16 ≠ 8    Therefore, its not a right angle triangle.

(D) Set (4) ⇒ 9 ft, √26 ft, 6 ft.

                      9² = (√26)² + 6²

                      81 = 26 + 36

                      81 ≠ 62   Therefore, its not a right angle triangle.

zhuklara [117]3 years ago
4 0

To be a right triangle, the hypotenuse^2 must equal side1^2 + side2^2

Only set 2 meets these conditions

8, sq root (29), sq root (35) then squaring these:

64, 29, 35

64 = 29 + 35

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bagirrra123 [75]

Answer: Lucas biked 96 miles.

Step-by-step explanation:

So, to get the anwser you need to first multiply Isabel’s miles by 4 to get Aiden’s miles so 6 x 4 = 24 miles so next you need to multiply aidens miles by 4 to get how many miles lucas biked which is 96 miles.

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I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ
Jobisdone [24]

Answer:

\frac{a(450-8a^2)}{4}

is the volume in terms of side a

Step-by-step explanation:

Given that you I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per square foot, the material for the roof cost $2 per square foot, and the material for the sides cost $2.50 per square foot; and I spent $450 altogether on material for the shed.

Let a be the side of square and h be the height

Total cost of materials = cost for floor + cost for roof + cost for sides

= area of floor (4) + lateral area (2.50)+roof area (2)

=4a^2+4ah+4a^2\\=8a^2+4ah = 450h = \frac{450-8a^2}{4a}

Now coming to volume

Volume = V = lbh = a^2 h\\= a^2*\frac{450-8a^2}{4a} \\=\frac{a(450-8a^2)}{4}

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3 years ago
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jasenka [17]
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3 0
4 years ago
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The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te
kozerog [31]

Answer:

\dfrac{6}{7}.

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

a_n=ar^{n-1}

a+ar=6     ...(1)

Each term is 5 times the sum of the succeeding terms.

a_n=5(a_{n+1}+a_{n+2}+...+\infty)

ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)

ar^{n-1}=5ar^n(1+r+r^2+...+\infty)

Divide both sides by a.

r^{n-1}=5r^n(\dfrac{1}{1-r})    [\text{Sum of infinite GP}=\dfrac{a}{1-r}]

\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}

\dfrac{1}{r}=\dfrac{5}{1-r}

1-r=5r

1=6r

\dfrac{1}{6}=r

The common ratio is 1/6.

Put r=1/6 in (1).

a+a(\dfrac{1}{6})=6

6a+a=36

7a=36

a=\dfrac{36}{7}

Second term ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}

Therefore, the second term is \dfrac{6}{7}.

4 0
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The perimeter of a given rectangle is at least 50 cm. The length of the rectangle is one more than 3 times the width of the rect
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Answer:

The minimum length is 19 cm and the minimum width is 6 cm


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