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True [87]
3 years ago
5

Which one of these four sets of side lengths will form a right triangle?

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0

Answer:

Option B is the answer.

Step-by-step explanation:

We know in a right angle triangle when we apply Pythagoras Theorem, then

(Hypotenuse)² = ( side 1)² + (side 2)²

(A) set (1) ⇒ 6 cm, 7 cm, √12 cm

7² = 6² + (√12)²

49 = 36 + 12 = 48

49 ≠ 48     Therefore, its not the sides of a right triangle.

(B) Set (2) ⇒ 8 in, √29 in, √35 in

                    8² = (√29)² + (√35)²

                  64 = 29 + 35

                   64 = 64    So its a right angle triangle

(C) Set (3) ⇒ √3 mm, 4 mm √5 mm

         4² = (√3)² + (√5)²

         16 = 3 + 5

         16 ≠ 8    Therefore, its not a right angle triangle.

(D) Set (4) ⇒ 9 ft, √26 ft, 6 ft.

                      9² = (√26)² + 6²

                      81 = 26 + 36

                      81 ≠ 62   Therefore, its not a right angle triangle.

zhuklara [117]3 years ago
4 0

To be a right triangle, the hypotenuse^2 must equal side1^2 + side2^2

Only set 2 meets these conditions

8, sq root (29), sq root (35) then squaring these:

64, 29, 35

64 = 29 + 35

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The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

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Let suppose the other polynomial addend is f(a,b). Thus,

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Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

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