The answer is B.
remember to use the reciprocal when dividing with fractions
(a)
We can see that
this is a straight line
and this is the graph of velocity
we know that
acceleration is the derivative of velocity
so, slope of curve of velocity is acceleration
so, we will find slope of this line
We can select any two points
(0,4) and (5,7)
we can use slope formula
now, we can plug points
we know that slope of line is always constant irrespective of any value of t
so, acceleration will always be same irrespective of any value of t
so, we will get acceleration
............Answer
(b)
we can see that acceleration is constant
and we know that
derivative of constant is always 0
so, instantaneous rate of acceleration at t=10s is 0........Answer
Answer:
- g = -1110p +4300.9
- 804 gallons
Step-by-step explanation:
a) Price is the independent variable, so the data we are given can be written as ...
(price, gallons) = (2.99, 982) and (2.79, 1204)
Using the 2-point form of the equation for a line, we have ...
g = (g2 -g1)/(p2 -p1)(p -p1) +g1
g = (1204 -982)/(2.79 -2.99)(p -2.99) +982
g = -1110(p -2.99) +982 = -1110p +4300.9
g = -1110p +4300.9
__
b) When p = 3.15, the predicted sales volume is ...
g = -1110(3.15) +4300.9 = 804.4
Weekly sales are predicted to be 804 gallons at a price of $3.15.
The x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is (17, 11)
<h3>Midpoint of coordinate points</h3>
The midpoint of a line is the point that bisects or divides the line into two equal parts
If the line JK is partitioned into the ratio 1:4 with the following coordinates
J(-15, -5) and K(25, 15)
Using the expression below;
M(x, y) =[mx1+nx2/m+n, my1+ny2/m+n]
Substitute the ratio and the coordinates
M(x, y) =[1(-15)+4(25)/4+1, 1(-5)+4(15)/1+4]
M(x, y) = [(85)/5, 55/5]
M(x, y) = (17, 11)
Hence the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is ((17, 11)
Learn more on midpoint of a line here: brainly.com/question/5566419
#SPJ1
A cell with 2cm sides has a surface area of 6 × a2 or <span> a</span>2<span> + a</span>2<span> + a</span>2<span> + a</span>2<span> + a</span>2<span> + a</span><span>2
</span>
